Giải bài 1 trang 36

Đề bài

Tính giá trị biểu thức (theo cách hợp lí nếu có thể):

a) $204-72:12$

b) ${15.2}^3+{4.3}^2-5.7$

c)$3^5:3^2+2^3{.2}^2$

d)$6^3.57+{43.6}^3$

e)$21.7+21.2-11.(3^5:3^3)$

g)$327-27\left[\left(3^3+{2020}^0\right):7-2\right]$

Lời giải chi tiết

a) $204-72:12=204-6=198.$

b) ${15.2}^3+{4.3}^2-5.7=15.8+4.9-5.7=120+36-35=121$

c) $3^5:3^2+2^3{.2}^2=3^{5-2}+2^{3+2}=3^3+2^5=27+32=59$

d) $6^3.57+{43.6}^3=6^3.57+6^3.43=6^3.(57+43)=6^3.100=216.100=21600$

e)

$\begin{array}{c}21.7+21.2-11.(3^5:3^3)\\ =21.7+21.2-{11.3}^{5-3}\\ =21.7+21.2-{11.3}^2\\ =21.(7+2)-11.9\\ =21.9-11.9\\ =9.(21-11)\\ =9.10\\ =90\end{array}$

g)

 $\begin{array}{c}327-27\left[\left(3^3+{2020}^0\right):7-2\right]\\ =327-27\left[\left(27+1\right):7-2\right]\\ =327-27\left[28:7-2\right]\\ =327-27\left[4-2\right]\\ =327-27.2\\ =327-54\\ =273.\end{array}$