Giải bài 6.38 trang 26

Đề bài

Tính: a)$\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}$

b)$\frac{-3}{8}+\frac{7}{4}-\frac{1}{12}$

c)$\frac{3}{5}:(\frac{1}{4}.\frac{7}{5})$

d)$\frac{10}{11}+\frac{4}{11}:4-\frac{1}{8}$

Lời giải chi tiết

 a)$\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{-3}{6}+\frac{5}{6}+\frac{2}{6}=\frac{4}{6}=\frac{2}{3}$

b)$\frac{-3}{8}+\frac{7}{4}-\frac{1}{12}=\frac{-9}{24}+\frac{42}{24}-\frac{2}{24}=\frac{31}{24}$

c)$\frac{3}{5}:(\frac{1}{4}.\frac{7}{5})=\frac{3}{5}:\frac{7}{20}=\frac{3}{5}.\frac{20}{7}=\frac{12}{7}$

d)$\frac{10}{11}+\frac{4}{11}:4-\frac{1}{8}=\frac{10}{11}+\frac{4}{11}.\frac{1}{4}-\frac{1}{8}=\frac{10}{11}+\frac{1}{11}-\frac{1}{8}=1-\frac{1}{8}=\frac{7}{8}$